Integrand size = 19, antiderivative size = 40 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {(2 A+C) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {C \sec (c+d x) \tan (c+d x)}{2 d} \]
[Out]
Time = 0.03 (sec) , antiderivative size = 40, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.105, Rules used = {4131, 3855} \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {(2 A+C) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {C \tan (c+d x) \sec (c+d x)}{2 d} \]
[In]
[Out]
Rule 3855
Rule 4131
Rubi steps \begin{align*} \text {integral}& = \frac {C \sec (c+d x) \tan (c+d x)}{2 d}+\frac {1}{2} (2 A+C) \int \sec (c+d x) \, dx \\ & = \frac {(2 A+C) \text {arctanh}(\sin (c+d x))}{2 d}+\frac {C \sec (c+d x) \tan (c+d x)}{2 d} \\ \end{align*}
Time = 0.01 (sec) , antiderivative size = 48, normalized size of antiderivative = 1.20 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {A \text {arctanh}(\sin (c+d x))}{d}+\frac {C \text {arctanh}(\sin (c+d x))}{2 d}+\frac {C \sec (c+d x) \tan (c+d x)}{2 d} \]
[In]
[Out]
Time = 0.12 (sec) , antiderivative size = 55, normalized size of antiderivative = 1.38
method | result | size |
derivativedivides | \(\frac {A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}\) | \(55\) |
default | \(\frac {A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )+C \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}\) | \(55\) |
parts | \(\frac {A \ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{d}+\frac {C \left (\frac {\sec \left (d x +c \right ) \tan \left (d x +c \right )}{2}+\frac {\ln \left (\sec \left (d x +c \right )+\tan \left (d x +c \right )\right )}{2}\right )}{d}\) | \(57\) |
parallelrisch | \(\frac {-\left (A +\frac {C}{2}\right ) \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )+\left (A +\frac {C}{2}\right ) \left (1+\cos \left (2 d x +2 c \right )\right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )+C \sin \left (d x +c \right )}{d \left (1+\cos \left (2 d x +2 c \right )\right )}\) | \(86\) |
norman | \(\frac {\frac {C \tan \left (\frac {d x}{2}+\frac {c}{2}\right )}{d}+\frac {C \tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{3}}{d}}{\left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )^{2}-1\right )^{2}}-\frac {\left (2 A +C \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )-1\right )}{2 d}+\frac {\left (2 A +C \right ) \ln \left (\tan \left (\frac {d x}{2}+\frac {c}{2}\right )+1\right )}{2 d}\) | \(93\) |
risch | \(-\frac {i C \left ({\mathrm e}^{3 i \left (d x +c \right )}-{\mathrm e}^{i \left (d x +c \right )}\right )}{d \left ({\mathrm e}^{2 i \left (d x +c \right )}+1\right )^{2}}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) A}{d}-\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}-i\right ) C}{2 d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) A}{d}+\frac {\ln \left ({\mathrm e}^{i \left (d x +c \right )}+i\right ) C}{2 d}\) | \(118\) |
[In]
[Out]
none
Time = 0.27 (sec) , antiderivative size = 72, normalized size of antiderivative = 1.80 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {{\left (2 \, A + C\right )} \cos \left (d x + c\right )^{2} \log \left (\sin \left (d x + c\right ) + 1\right ) - {\left (2 \, A + C\right )} \cos \left (d x + c\right )^{2} \log \left (-\sin \left (d x + c\right ) + 1\right ) + 2 \, C \sin \left (d x + c\right )}{4 \, d \cos \left (d x + c\right )^{2}} \]
[In]
[Out]
\[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\int \left (A + C \sec ^{2}{\left (c + d x \right )}\right ) \sec {\left (c + d x \right )}\, dx \]
[In]
[Out]
none
Time = 0.21 (sec) , antiderivative size = 58, normalized size of antiderivative = 1.45 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {{\left (2 \, A + C\right )} \log \left (\sin \left (d x + c\right ) + 1\right ) - {\left (2 \, A + C\right )} \log \left (\sin \left (d x + c\right ) - 1\right ) - \frac {2 \, C \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \]
[In]
[Out]
none
Time = 0.30 (sec) , antiderivative size = 60, normalized size of antiderivative = 1.50 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {{\left (2 \, A + C\right )} \log \left ({\left | \sin \left (d x + c\right ) + 1 \right |}\right ) - {\left (2 \, A + C\right )} \log \left ({\left | \sin \left (d x + c\right ) - 1 \right |}\right ) - \frac {2 \, C \sin \left (d x + c\right )}{\sin \left (d x + c\right )^{2} - 1}}{4 \, d} \]
[In]
[Out]
Time = 16.08 (sec) , antiderivative size = 41, normalized size of antiderivative = 1.02 \[ \int \sec (c+d x) \left (A+C \sec ^2(c+d x)\right ) \, dx=\frac {\mathrm {atanh}\left (\sin \left (c+d\,x\right )\right )\,\left (A+\frac {C}{2}\right )}{d}-\frac {C\,\sin \left (c+d\,x\right )}{2\,d\,\left ({\sin \left (c+d\,x\right )}^2-1\right )} \]
[In]
[Out]